Question

Задача!За 6 минут самолёт пролетел 102 км.Какое расстояние пролетит самолёт за 42 мин,если его скорость увеличивается на 2 км/мин?

Answer 1

102÷6 скорость и скорость×42+2×42

Answer 2

102/6=17
17+2=19
19*42=798 км

Answer 3

Problem Analysis

We are given that a plane traveled 102 km in 6 minutes. We need to find the distance the plane will travel in 42 minutes, assuming its speed increases by 2 km/min.

Solution

To solve this problem, we can use the formula for distance, speed, and time:

Distance = Speed × Time

Let's calculate the distance the plane will travel in 42 minutes.

Given: - Initial speed = unknown - Initial time = 6 minutes - Initial distance = 102 km - Final time = 42 minutes - Speed increase = 2 km/min

To find the initial speed, we can rearrange the formula:

Initial Speed = Initial Distance / Initial Time

Substituting the given values:

Initial Speed = 102 km / 6 min

Now, we can calculate the initial speed:

Initial Speed = 17 km/min To find the final distance, we can use the formula:

Final Distance = (Initial Speed + Speed Increase) × Final Time

Substituting the given values:

Final Distance = (17 km/min + 2 km/min) × 42 min

Now, we can calculate the final distance:

Final Distance = 19 km/min × 42 min

Final Distance = 798 km

Therefore, the plane will travel 798 km in 42 minutes, assuming its speed increases by 2 km/min.

Answer

The plane will travel 798 km in 42 minutes, assuming its speed increases by 2 km/min.

References

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