
Решите пожалуйста задачу По двум параллельным железнодорожным путям в одном направлении следуют
пассажирский и товарный поезда, скорости которых равны соответственно 190 км/ч и 40 км/ч. Длина товарного поезда равна 1550 метрам. Найдите длину пассажирского поезда, если время, за которое он прошел мимо товарного поезда, равно 1 минуте. Ответ дайте в метрах.

Ответы на вопрос

2)пассажирский обогнал товарный за 1 мин=1/60 часа,за это время он прошел длину товарного 1550м(1,55 км)и свою собственную длину,ее и обозначим х км: 150*1/60=1,55+х
решим уравнение
1,55+х=2,5
х=2,5-1,55
х=0,95 км или 950 м длина пассажирского поезда.



Problem Analysis
We are given two parallel railway tracks, and a passenger train and a freight train are traveling in the same direction on these tracks. The speeds of the trains are given as 190 km/h and 40 km/h, respectively. The length of the freight train is 1550 meters. We need to find the length of the passenger train, given that it takes 1 minute for the passenger train to pass the freight train.Solution
To solve this problem, we can use the concept of relative speed. The relative speed of the passenger train with respect to the freight train is the difference between their speeds. Let's calculate the relative speed:Relative speed = Speed of passenger train - Speed of freight train
Using the given speeds, we have:
Relative speed = 190 km/h - 40 km/h
Now, we need to convert the relative speed to meters per minute, as the time is given in minutes. To do this, we can use the conversion factor: 1 km/h = (1000/60) m/min.
Relative speed = (190 km/h - 40 km/h) * (1000/60) m/min
Next, we can calculate the distance traveled by the passenger train in 1 minute. The distance traveled is equal to the length of the freight train plus the length of the passenger train.
Distance traveled by passenger train = Length of freight train + Length of passenger train
We are given the length of the freight train as 1550 meters. Let's substitute the values and solve for the length of the passenger train.
Calculation
Relative speed = (190 km/h - 40 km/h) * (1000/60) m/minDistance traveled by passenger train = 1550 meters + Length of passenger train
Solution Steps
1. Calculate the relative speed using the given speeds. 2. Convert the relative speed to meters per minute. 3. Substitute the values into the equation for the distance traveled by the passenger train. 4. Solve for the length of the passenger train.Calculation
1. Relative speed = (190 km/h - 40 km/h) * (1000/60) m/min - Relative speed = 150 km/h * (1000/60) m/min - Relative speed = 2500 m/min2. Distance traveled by passenger train = 1550 meters + Length of passenger train
3. Substitute the relative speed and distance traveled into the equation: - 2500 m/min = 1550 meters + Length of passenger train
4. Solve for the length of the passenger train: - Length of passenger train = 2500 m/min - 1550 meters - Length of passenger train = 950 meters
Answer
The length of the passenger train is 950 meters.Note: The answer is based on the given information and calculations.


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