Question

Помогииитеее!! A) sinα cosα tgα =?? Б) sinα cosα ctgα -1 =??

Answer 1

$sinacosa \frac{sina}{cosa} =sin a^{2} </span>[tex]2. = sina cosa \frac{cosa}{sina} -sin a^{2} -cos a^{2} =-sin a^{2}$

Answer 2

A) sinα cosα tgα = ?

The expression sinα cosα tgα can be simplified using trigonometric identities.

One of the trigonometric identities states that tgα = sinα / cosα.

Substituting this into the expression, we get:

sinα cosα tgα = sinα cosα (sinα / cosα) = sinα^2

Therefore, sinα cosα tgα simplifies to sinα^2.

B) sinα cosα ctgα - 1 = ?

To simplify the expression sinα cosα ctgα - 1, we need to use the trigonometric identity ctgα = cosα / sinα.

Substituting this into the expression, we get:

sinα cosα ctgα - 1 = sinα cosα (cosα / sinα) - 1 = cosα^2 - 1

Therefore, sinα cosα ctgα - 1 simplifies to cosα^2 - 1.

Please let me know if there's anything else I can help#### A) sinα cosα tgα = ?

The expression sinα cosα tgα represents the product of the sine of α, the cosine of α, and the tangent of α. To simplify this expression, we can use trigonometric identities.

One of the trigonometric identities that can be helpful here is:

tanα = sinα / cosα

Using this identity, we can rewrite the expression as:

sinα cosα tgα = sinα cosα (sinα / cosα)

The cosα terms cancel out, leaving us with:

sinα cosα tgα = sinα sinα

And since sinα sinα is equal to sin²α, the simplified expression is:

sinα cosα tgα = sin²α

Therefore, sinα cosα tgα is equal to sin²α.