Question

Реактивный самолет за 1/5 часа пролетает 180 км. найдите расстояние между аэрапортами. если известно. что пункта А самолет вылетел в 16 часов 40 мин. а посадку в пункте В совершил в 21 час 40 мин?

Answer 1

1) 21ч40мин - 16ч 40мин = 5(час) был в полёте самолёт
2) 1/5 часа = 60 : 5 = 12(мин)
     5час. =300мин
3) 300 : 12 = 25(раз) умещается 12 мин. в 5 часах
4) 180 * 25 = 4500(км)
Ответ: 4500 км - расстояние между аэропортами.

Answer 2

Problem Analysis

We are given that a jet plane travels 180 km in 1/5 of an hour. We need to find the distance between two airports, given that the plane took off from Airport A at 16:40 and landed at Airport B at 21:40.

Solution

To find the distance between the airports, we need to calculate the total time the plane was in the air and then use the given speed to find the distance.

1. Calculate the time the plane was in the air: - The plane took off from Airport A at 16:40 and landed at Airport B at 21:40. - The difference between these two times is 5 hours. - Convert the minutes to hours: 40 minutes is 40/60 = 2/3 hours. - Therefore, the total time the plane was in the air is 5 hours + 2/3 hours = 5 2/3 hours.

2. Calculate the speed of the plane: - We are given that the plane travels 180 km in 1/5 of an hour. - To find the speed, divide the distance by the time: 180 km / (1/5) hour = 900 km/hour.

3. Calculate the distance between the airports: - Multiply the speed of the plane by the total time in the air: 900 km/hour * 5 2/3 hours. - Convert the mixed fraction to an improper fraction: 5 2/3 = (5 * 3 + 2) / 3 = 17/3. - Multiply the speed by the time: 900 km/hour * 17/3 hours = 5100 km.

Answer

The distance between Airport A and Airport B is 5100 km.

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