Question

Решите задачу:Из 2-х посёлков расстояние между которыми 156 км.Одновременно навстречу друг другу вышли 2 пешехода и встретились через полтора часа. Найдите скорость каждого пешехода, если скорость одного из них в 1,4 раза больше скорости другого.

Answer 1

Пусть х км/ч скорость 1 пешехода , второго 1,4х км/ч
(х+1,4х)*1,5=156
2,4х=104
х=43 1/3 км/ч ,у другого 
43 1/3*1,5=65 км/ч

задача не похожа на реальность , может это 2 автомобиля двигались?

Answer 2

Problem Analysis

We are given that the distance between two villages is 156 km. Two pedestrians start walking towards each other from these villages and meet after 1.5 hours. We need to find the speed of each pedestrian, given that the speed of one pedestrian is 1.4 times the speed of the other.

Solution

Let's assume the speed of the slower pedestrian is x km/h. Then the speed of the faster pedestrian would be 1.4x km/h.

We can use the formula distance = speed × time to solve this problem.

The distance covered by the slower pedestrian in 1.5 hours is 1.5x km, and the distance covered by the faster pedestrian in 1.5 hours is 1.5 × 1.4x km.

Since they are walking towards each other, the sum of the distances covered by both pedestrians should be equal to the total distance between the villages, which is 156 km.

Therefore, we can write the equation:

1.5x + 1.5 × 1.4x = 156

Simplifying the equation:

1.5x + 2.1x = 156

3.6x = 156

Dividing both sides of the equation by 3.6:

x = 156 / 3.6

Evaluating the expression:

x ≈ 43.33

So, the speed of the slower pedestrian is approximately 43.33 km/h, and the speed of the faster pedestrian is approximately 1.4 × 43.33 ≈ 60.66 km/h.

Therefore, the speed of each pedestrian is approximately 43.33 km/h and 60.66 km/h.

Answer

The speed of the slower pedestrian is approximately 43.33 km/h, and the speed of the faster pedestrian is approximately 60.66 km/h.