Question

Три пятиклассника купили 14 пирожков, причём Коля купил в 2 раза меньше пирожков, чем Вася, а Женя больше Коли, но меньше Васи. Сколько пирожков купил каждый из них?

Answer 1

Коля 3 Вася 6 Женя 5. Подбором Коля 3 Вася 3*2+=6 Вася 14-(3*2) = 5

Answer 2

14 вычесть 2 равно 12 а потом  а женя купил 13 пирожков

Answer 3

Problem Analysis

We are given that three fifth-graders, Kolya, Vasya, and Zhenya, bought a total of 14 pies. Kolya bought half as many pies as Vasya, and Zhenya bought more pies than Kolya but fewer than Vasya. We need to determine how many pies each of them bought.

Solution

Let's assign variables to represent the number of pies bought by each student: - Let K represent the number of pies bought by Kolya. - Let V represent the number of pies bought by Vasya. - Let Z represent the number of pies bought by Zhenya.

From the given information, we can form the following equations: 1. K + V + Z = 14 (the total number of pies bought is 14). 2. K = V/2 (Kolya bought half as many pies as Vasya). 3. Z > K (Zhenya bought more pies than Kolya). 4. Z < V (Zhenya bought fewer pies than Vasya).

To solve this system of equations, we can use substitution. Let's substitute the value of K from equation 2 into equations 3 and 4.

From equation 2, we have K = V/2. Substituting this into equation 3, we get Z > V/2. Multiplying both sides by 2, we have 2Z > V.

Similarly, substituting K = V/2 into equation 4, we get Z < V/2. Multiplying both sides by 2, we have 2Z < V.

Combining the inequalities, we have 2Z > V > 2Z. This means that V must be equal to 2Z.

Now, let's substitute the value of V = 2Z into equation 1 to solve for Z.

K + V + Z = 14 K + 2Z + Z = 14 K + 3Z = 14

Since K = V/2, we can substitute V = 2Z into the equation above:

V/2 + 3Z = 14 2Z/2 + 3Z = 14 Z + 3Z = 14 4Z = 14 Z = 14/4 Z = 3.5

Since we cannot have a fraction of a pie, Zhenya cannot have bought 3.5 pies. Therefore, there is no solution to this problem.

Answer

There is no solution to the problem. It is not possible to determine how many pies each of the three fifth-graders bought given the information provided.