Question

Квартира состоит из трёх комнат.Первая комната на 5 м2(в квадрате) меньше второй,а вторая на 8 м2(в квадрате) меньше третей.Найдите общую площадь трёх комнат,если площадь самой маленькой из них 10 м2(в квадрате)

Answer 1

х - площадь первой

х+5 - площадь второй

х+5+8=х+13 - площадь третей

х+х+5+х+13=3х+18=3*10+18=48 кв м - площадь общая

Answer 2

1-я комната меньше 2, а 2 меньше 3-ей, вывод -  самая маленькая

1-я комната = 10 (кв.м)

10+5=15 (кв.м) - 2-я комната

15+8=23 (кв.м) - 3-я комната

10+15+23=48 (кв.м) - площадь трех комнат

Answer 3

Calculation of the Total Area of the Three Rooms

To find the total area of the three rooms, we need to determine the area of each room and then add them together.

Let's denote the area of the first room as x square meters, the area of the second room as y square meters, and the area of the third room as z square meters.

According to the given information, the first room is 5 square meters smaller than the second room, and the second room is 8 square meters smaller than the third room.

Therefore, we can express the areas of the three rooms as follows:

- First room: x - Second room: x + 5 - Third room: x + 5 + 8 = x + 13

We also know that the area of the smallest room is 10 square meters. So we can set up the equation:

x = 10

Now we can substitute this value of x into the expressions for the areas of the second and third rooms:

- Second room: 10 + 5 = 15 - Third room: 10 + 13 = 23

Therefore, the areas of the three rooms are:

- First room: 10 square meters - Second room: 15 square meters - Third room: 23 square meters

To find the total area of the three rooms, we add these areas together:

10 + 15 + 23 = 48 square meters

Therefore, the total area of the three rooms is 48 square meters.