
в первый день мастер выполнил 3/10 всей работы,а во второй день в 2 раза больше,чем в первый.Успел
ли мастер выполнить задание за 2 дня? напишите подробно решение пожалуйста

Ответы на вопрос

3/10х2= 6/10=3/5 сделал во второй день
6/10+3/10=9/10 работы он сделает за 2 дня, следовательно он не успеет сделать всю работу, так как ему не хватит 1/10.



3/10*2=6/10 за второй день
6/10+3/10=9/10нет не успеет



Problem Analysis
The problem states that on the first day, a master completed 3/10 of the total work, and on the second day, the master completed twice as much work as on the first day. The question is whether the master was able to complete the task in two days.Solution
To determine if the master completed the task in two days, we need to calculate the total amount of work completed in two days and compare it to the total work required.Let's assume that the total work required is represented by the variable W.
On the first day, the master completed 3/10 of the total work, which can be represented as (3/10)W.
On the second day, the master completed twice as much work as on the first day, which is 2 * (3/10)W = (6/10)W.
To find the total work completed in two days, we add the work completed on the first day and the work completed on the second day:
(3/10)W + (6/10)W = (9/10)W
Therefore, the master completed (9/10)W of the total work in two days.
To determine if the master completed the task, we need to compare the total work completed in two days to the total work required.
If (9/10)W is equal to or greater than W, then the master completed the task in two days.
Conclusion
Based on the calculations, the master completed (9/10)W of the total work in two days. Whether the master completed the task or not depends on the value of (9/10)W compared to W. If (9/10)W is equal to or greater than W, then the master completed the task in two days.Please note that the actual value of W is not provided in the problem statement, so we cannot determine the exact outcome without that information.
Let me know if there's anything else I can help you with!


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