Question

Помогите отблагодарю... Не могу решить самостоятельную работу помогите плииииз 1)реши уравнение: 2,3у+5,1+ 3,7у+9,9=18,32) Сумма цифр трехзначного числа равна 7, а произведение-8. Какое это число? Найди все возможные варианты.3)Переведи условия задачи на матиматический язык: Ученик делал в течение первых 2 часов по m деталий в час, а в слудующие 3часа- по n деталий в час. За сколько времени может сделать эту же работу мастер, если его производительность d деталий в час?

Answer 1

1)2.3у+3.7у+5.1+9.9=18.3        2)1+2+4=7                                3)(2m+3n):d
   6у+15=18.3                             1*2*4=8       
   6у=18.3-15                               124,142,214,241,412,421
   6у=3.3                                     
    у=3.3:6
   у=0.55

Answer 2

It looks like you need help with some math problems. I'd be happy to assist you with that! Let's tackle each question one by one.

1) Solve the equation: 2.3y + 5.1 + 3.7y = 18.3

To solve this equation, we can combine like terms and then solve for y.

First, combine the y terms: 2.3y + 3.7y = 6y

Now, rewrite the equation with the combined y terms: 6y + 5.1 = 18.3

Subtract 5.1 from both sides of the equation: 6y = 13.2

Finally, divide both sides by 6 to solve for y: y = 13.2 / 6 y = 2.2

The solution to the equation is y = 2.2.

[[1 #]]

2) Find all possible three-digit numbers where the sum of the digits is 7 and the product of the digits is 8.

To find all possible three-digit numbers that satisfy these conditions, we can start by listing the combinations of digits that sum to 7 and have a product of 8.

The possible combinations are: 1. 1 + 2 + 4 = 7 (Product: 1 * 2 * 4 = 8) 2. 1 + 4 + 2 = 7 (Product: 1 * 4 * 2 = 8) 3. 2 + 1 + 4 = 7 (Product: 2 * 1 * 4 = 8) 4. 2 + 4 + 1 = 7 (Product: 2 * 4 * 1 = 8) 5. 4 + 1 + 2 = 7 (Product: 4 * 1 * 2 = 8) 6. 4 + 2 + 1 = 7 (Product: 4 * 2 * 1 = 8)

So, the possible three-digit numbers are 124, 142, 214, 241, 412, and 421.

The possible three-digit numbers are 124, 142, 214, 241, 412, and 421.

[[2 #]]

3) Translate the problem into mathematical language:

A student made m parts per hour for the first 2 hours and n parts per hour for the next 3 hours. How long would it take a master, who can make d parts per hour, to complete the same work?

In mathematical terms, we can represent the total number of parts made by the student and the master as follows: Total parts made by the student = 2m + 3n Total parts made by the master = x * d, where x is the time in hours taken by the master to complete the work.

To find the time taken by the master, we can set up the equation: 2m + 3n = x * d

Solving for x, we get: x = (2m + 3n) / d

The master can complete the work in (2m + 3n) / d hours.

[[3 #]]

I hope these explanations help! If you have any more questions or need further assistance, feel free to ask.