Question

Из поселка А в 10 часов утра выехал велосипедист со скоростью 12 км в час... В 12 часовв том же направлении выехал второй велосипедист скорость которого на 3 км в час больше. Кто из них приедет в поселок первым, если расстояния между поселками 60 км.

Answer 1

12-10=2 2*12=24 60-24=36 36=3часам 12+3=15 60:15=4часа ответ: первый велосипедист

Answer 2

ВТОРОЙ ВЕЛОСЕПЕДИСТ ПЕРВЫЙ

Answer 3

Problem Analysis

We are given that a cyclist from village A starts at 10:00 AM with a speed of 12 km/h. Another cyclist starts at 12:00 PM in the same direction with a speed that is 3 km/h faster. We need to determine which cyclist will reach the village first, given that the distance between the villages is 60 km.

Solution

To solve this problem, we can calculate the time it takes for each cyclist to reach the village and compare their arrival times.

Let's start by calculating the time it takes for the first cyclist to reach the village. We can use the formula:

Time = Distance / Speed

For the first cyclist: - Distance = 60 km - Speed = 12 km/h

Substituting these values into the formula, we get:

Time for the first cyclist = 60 km / 12 km/h = 5 hours

Now, let's calculate the time it takes for the second cyclist to reach the village. We know that the second cyclist's speed is 3 km/h faster than the first cyclist's speed, so the speed of the second cyclist is:

Speed = 12 km/h + 3 km/h = 15 km/h

Using the same formula as before, we can calculate the time for the second cyclist:

Time for the second cyclist = 60 km / 15 km/h = 4 hours

Comparing the arrival times, we can see that the second cyclist will reach the village first, as they will take 4 hours compared to the first cyclist's 5 hours.

Therefore, the second cyclist will arrive in the village first.

Answer

The second cyclist will arrive in the village first.