Question

Периметр прямокутника дорівнює 20 см, знайдіть довжину прямокутника., якщо вона більша на 2 см за його ширину

Answer 1

Пусть ширина= х, тогда длина= х=2
Р=(х+х+2)*2
2х+2х+4=20
4х=16
х=4
Значит, ширина=4 см, а длина=6 см.

Answer 2

Ширина х см , то довжина 2+х см.Маємо рівняння :
                                                    2+х+2+х+х+х=20
                                                    4х=20-4
                                                    х=16:4
                                                    х=4
Ширина 4 см , а довжина 4+2=6 см

Answer 3

Finding the Length of a Rectangle

To find the length of a rectangle when the perimeter is 20 cm and it is 2 cm longer than its width, we can use the formula for the perimeter of a rectangle, which is given by:

Perimeter = 2 * (Length + Width)

Let's denote the width of the rectangle as w. According to the problem, the perimeter is 20 cm, so we have:

20 = 2 * (Length + Width)

Since the length is 2 cm longer than the width, we can express the length as w + 2. Substituting this into the equation, we get:

20 = 2 * (w + (w + 2))

Simplifying the equation, we have:

20 = 2 * (2w + 2)

Dividing both sides of the equation by 2, we get:

10 = 2w + 2

Subtracting 2 from both sides of the equation, we have:

8 = 2w

Dividing both sides of the equation by 2, we get:

w = 4

Therefore, the width of the rectangle is 4 cm. Since the length is 2 cm longer than the width, the length of the rectangle is:

Length = Width + 2 = 4 + 2 = 6 cm

So, the length of the rectangle is 6 cm.