Question

Два сплава состоят из серебра и золота находящуюся в разных соотношениях в первом 60% золота во втором 80% серебра сколько граммов сплава нужно взять чтобы получить 30 грамм нового сплава с 30% содержанием золота

Answer 1

30 грамм: 100=0,3
0,3 умнож. на 30=9 гр.
30-9=21
 

Answer 2

Calculating the Amount of Alloy Needed

To calculate the amount of alloy needed to obtain a new alloy with a 30% gold content, we can use the concept of the conservation of mass.

Let's assume we need to obtain 30 grams of the new alloy with a 30% gold content. We are given two alloys: one with 60% gold and the other with 80% silver.

To solve this problem, we can set up an equation based on the conservation of mass:

Amount of gold in the first alloy + Amount of gold in the second alloy = Amount of gold in the new alloy

Let's denote the amount of the first alloy as 'x' grams. Since the first alloy contains 60% gold, the amount of gold in the first alloy is 0.6x grams.

Similarly, the amount of the second alloy is (30 - x) grams, and since the second alloy contains 80% silver, the amount of gold in the second alloy is 0.2(30 - x) grams.

Now we can set up the equation:

0.6x + 0.2(30 - x) = 0.3(30)

Simplifying the equation:

0.6x + 6 - 0.2x = 9

0.4x = 3

x = 7.5

Therefore, we need to take 7.5 grams of the first alloy to obtain 30 grams of the new alloy with a 30% gold content.

Please note that the calculations are based on the assumption that the alloys are homogeneous and the gold and silver are evenly distributed within them.