Question

В 3 бидонах 90 л молока. После того как из 1 бидона отлили 8 л а из другого 12 л в каждом из них оказалось молока в 2 раза меньше чем в 3 бидоне .сколько литров молока было в каждом бидоне первоначально.

Answer 1

Пусть в 1ом и 2ом бидоне-х, тогда в 3ем-2х
Составим уравнение:
2х+х+х=70( т.к отлили из 1го-8 литров и из 2го-12 литров. Всего 8+12=20 (90-20=70)
4х=70
х=17,5 литров
1)17,5+8=25,5(л)-было первоначально в 1ом бидоне
2)17,5+ 12=29,5(л)-было первоначально во 2ом бидоне
3)17,5×2=35(л)- было в 3ем бидоне

ПРОВЕРКА:
25,5+29,5+35=90

Answer 2

Problem Analysis

We have three containers of milk, and after pouring 8 liters from one container and 12 liters from another, the amount of milk in each of these two containers is half of what remains in the third container. We need to determine the initial amount of milk in each container.

Solution

Let's assume the initial amount of milk in the third container is x liters. After pouring 8 liters from the first container and 12 liters from the second container, the amount of milk in each of these two containers is half of what remains in the third container.

So, the amount of milk in the first container after pouring is x - 8 liters, and the amount of milk in the second container is x - 12 liters. According to the problem, these amounts are half of what remains in the third container, which is x liters.

We can set up the following equations based on the given information:

1. x - 8 = (1/2)x 2. x - 12 = (1/2)x

Let's solve these equations to find the value of x.

Equation 1:

x - 8 = (1/2)x

Multiply both sides of the equation by 2 to eliminate the fraction:

2(x - 8) = x

Expand the equation:

2x - 16 = x

Subtract x from both sides:

x - 16 = 0

Add 16 to both sides:

x = 16

Equation 2:

x - 12 = (1/2)x

Multiply both sides of the equation by 2 to eliminate the fraction:

2(x - 12) = x

Expand the equation:

2x - 24 = x

Subtract x from both sides:

x - 24 = 0

Add 24 to both sides:

x = 24

Conclusion

Based on the equations, we have two possible values for x: 16 and 24. These values represent the initial amount of milk in the third container. To find the initial amount of milk in each container, we subtract 8 and 12 liters from these values, respectively.

Possible solutions: 1. Initial amount of milk in the first container: 16 - 8 = 8 liters Initial amount of milk in the second container: 16 - 12 = 4 liters Initial amount of milk in the third container: 16 liters

2. Initial amount of milk in the first container: 24 - 8 = 16 liters Initial amount of milk in the second container: 24 - 12 = 12 liters Initial amount of milk in the third container: 24 liters

Therefore, there are two possible sets of initial amounts of milk in each container: (8, 4, 16) liters and (16, 12, 24) liters.