Question

4^(x+1)+4^(x+2)=0 Помогите решить кратко

Answer 1

Решение смотри на фото

Answer 2

4x+4+4x+8=0
8x= -12
x= -1,5

Answer 3

Equation Solution

To solve the equation 4^(x+1) + 4^(x+2) = 0, we can simplify it by factoring out 4^(x+1):

4^(x+1) + 4^(x+2) = 0 4^(x+1)(1 + 4) = 0 4^(x+1)(5) = 0

Now, we can solve for x by setting each factor equal to zero:

4^(x+1) = 0 This equation has no real solutions because 4 raised to any power will always be positive.

5 = 0 This equation also has no real solutions because 5 is not equal to 0.

Therefore, the original equation 4^(x+1) + 4^(x+2) = 0 has no real solutions.

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