Question

Решите уравнения: 1) |х+3|=0; 2) |1+х|=0; 3) |х-3|+0,5=0,5пожалуйста, решите поскорее.

Answer 1

1) |х+3|=0
х+3=0
х=0-3
х=-3
Ответ:-3

2) |1+х|=0
1+х=0
х=0+2
х=2
Ответ:2

3)х-3|+0,5=0,5
х-3+0,5=0,5
х=0,5-0,5+3
х=3
Ответ:3

Answer 2

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Answer 3

Solving the Equations

1) |x + 3| = 0 The absolute value of any real number is always non-negative. The only real number whose absolute value is 0 is 0 itself. Therefore, the solution to the equation is: x = -3.

2) |1 + x| = 0 Similar to the previous equation, the absolute value of any real number is always non-negative. The only real number whose absolute value is 0 is 0 itself. Therefore, the solution to the equation is: x = -1.

3) |x - 3| + 0.5 = 0.5 Subtracting 0.5 from both sides of the equation gives: |x - 3| = 0 As discussed earlier, the only real number whose absolute value is 0 is 0 itself. Therefore, the solution to the equation is: x = 3.

These are the solutions to the given equations. If you have any more questions or need further assistance, feel free to ask!