Question

1.Один лещ в улове рыбаков весил в среднем 1,125(десятичные дроби) кг, а 5 окуне весили столько, сколько 3 леща.Рыбаки поймали 27 лещей и 45 окуней. Сколько весила вся пойманная рыба?2.Одна овца алтайской породы дает в среднем 6, 3 кг шерсти, а 7 овец грозненской породы дают столько шерсти, сколько овец алтайскойю Сколько шерсит могут дать 8500 овец алтайской породы и 6600 грозненской?

Answer 1

1)
27*1,125 = 30,375 - 27 лещей вес
3*1,125 = 3,375  - 5 окуней вес
45:5 = 9 - 5 окуней
9*3,375 = 30,375 - 45 окуней вес
30,375+30,375 = 60,75 - вес всей рыбы
Ответ: 60,75 кг

Answer 2

Problem 1: Weight of Caught Fish

To solve this problem, we need to find the total weight of the caught fish, given the average weight of a bream and the weight of five perches.

Let's break down the information provided: - The average weight of one bream is 1.125 kg. - The weight of five perches is the same as the weight of three breams. - The fishermen caught 27 breams and 45 perches.

To find the total weight of the caught fish, we can follow these steps:

1. Calculate the weight of three breams by multiplying the average weight of one bream by 3. 2. Calculate the weight of five perches by dividing the weight of three breams by 3 and multiplying it by 5. 3. Calculate the total weight of the caught fish by multiplying the weight of 27 breams by the average weight of one bream and adding it to the weight of five perches.

Let's perform the calculations:

1. Weight of three breams: 1.125 kg/bream * 3 breams = 3.375 kg. 2. Weight of five perches: (3.375 kg / 3 breams) * 5 perches = 5.625 kg. 3. Total weight of the caught fish: (27 breams * 1.125 kg/bream) + 5.625 kg = 30.375 kg.

Therefore, the total weight of the caught fish is 30.375 kg.