Question

Скорость движения точки изменяется по закону V= ( 3t2 + 2t + 1 ) м/с. Найти закон движения тела.

Answer 1

S=3t³/3+2t²/2+t+C=t³+t²+t+c  м
V проинтегрировано по dx

Answer 2

Finding the Equation of Motion for the Given Velocity Function

To find the equation of motion for the given velocity function V = 3t^2 + 2t + 1 m/s, we need to integrate the velocity function with respect to time to obtain the equation of motion.

Integration of the Velocity Function

The equation of motion can be obtained by integrating the given velocity function with respect to time. The integration of the velocity function V = 3t^2 + 2t + 1 m/s with respect to time will give us the equation of motion.

The integration of the velocity function yields the equation of motion as follows: S = t^3 + t^2 + t + C, where S represents the displacement and C is the constant of integration.

Conclusion

Therefore, the equation of motion for the given velocity function V = 3t^2 + 2t + 1 m/s is S = t^3 + t^2 + t + C, where S represents the displacement and C is the constant of integration.