
Охотничья собака увидела зайца.Их первоначальное расстояние было равно тому,что заяц прыгнет 15
раз,но заяц увидев собаку стал бежать.Если собака прыгнет 2 раза,то заяц прыгнет 3 раза.Расстояние 3 прыжков собаки равно расстоянию 7 прыжков зайца.Сколько раз нужно прыгнуть собаке чтобы дойти до зайца?

Ответы на вопрос




Problem Analysis
We are given the following information: - The initial distance between the hunting dog and the hare is equal to the number of jumps the hare will make, which is 15. - If the dog jumps 2 times, the hare will jump 3 times. - The distance covered by the dog in 3 jumps is equal to the distance covered by the hare in 7 jumps.We need to determine how many jumps the dog needs to catch up to the hare.
Solution
Let's assume that the distance covered by the dog in x jumps is equal to the distance covered by the hare in y jumps.From the given information, we can set up the following equations: 1. The initial distance between the dog and the hare: x = 15 2. If the dog jumps 2 times, the hare jumps 3 times: 2x = 3y 3. The distance covered by the dog in 3 jumps is equal to the distance covered by the hare in 7 jumps: 3x = 7y
To solve this system of equations, we can use substitution or elimination.
Let's solve it using substitution: From equation 1, we have x = 15. Substituting x = 15 into equation 2, we get 2(15) = 3y. Simplifying, we have 30 = 3y. Dividing both sides by 3, we get y = 10.
So, the hare covers a distance of 10 jumps in the same distance that the dog covers in 15 jumps.
Now, let's find the number of jumps the dog needs to catch up to the hare. From equation 3, we have 3x = 7y. Substituting y = 10, we get 3x = 7(10). Simplifying, we have 3x = 70. Dividing both sides by 3, we get x = 23.33.
Since the number of jumps must be a whole number, we round up to the nearest whole number. Therefore, the dog needs to jump 24 times to catch up to the hare.
Answer
The dog needs to jump 24 times to catch up to the hare.Note: The solution assumes that the distance covered by the dog and the hare in each jump is the same.


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