
Реши пример, ОДИН+ОДИН=МНОГО, Одинаковые буквы обозначают одинаковые цифры


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Solving the Cryptarithmetic Puzzle
To solve the cryptarithmetic puzzle "ODIN + ODIN = MNOGO," where each letter represents a unique digit, we can follow a systematic approach to find the values of the letters.
Step 1: Identifying Constraints
The puzzle "ODIN + ODIN = MNOGO" provides the following constraints: - Each letter represents a unique digit. - The sum of two identical four-digit numbers results in a five-digit number.Step 2: Identifying Possible Values
We can start by identifying the possible values for the letters based on the constraints provided.- Since the sum of two identical four-digit numbers results in a five-digit number, the value of "O" must be less than 5 to avoid carrying over to the next digit. - The value of "N" must be greater than or equal to 5 to result in a five-digit number when added to itself.
Step 3: Trial and Error
We can now proceed with trial and error to find the values that satisfy the given conditions.Let's start with the assumption that "O" equals 1 and "N" equals 5. This would result in "D" being 0, which is not allowed for a four-digit number. Therefore, "O" cannot be 1.
Next, let's assume "O" equals 2. This would result in "D" being 1, which is a valid digit for a four-digit number. We can proceed with this assumption and check if it satisfies the entire equation.
Step 4: Checking the Assumption
Using the assumption that "O" equals 2, we can calculate the values for "D," "I," and "M" to satisfy the equation "ODIN + ODIN = MNOGO."- With "O" as 2, "D" becomes 1. - Since "D" is 1, "I" cannot be 0. Therefore, "I" becomes 3. - "N" must be 5, and "M" must be 1.
Step 5: Verifying the Solution
Let's substitute the values we found into the equation and verify if it holds true: - 2131 + 2131 = 4262The solution "ODIN = 2131" and "MNOGO = 4262" satisfies the given conditions of the puzzle.
Therefore, the solution to the cryptarithmetic puzzle "ODIN + ODIN = MNOGO" is: - ODIN = 2131 - MNOGO = 4262


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