Question

Дети собирали металлолом. Коля собрал на 3,5 кг больше, чем Кирилл, а Таня в два раза больше чем Коля. Сколько собрал металлолома Коля, если втроем они собрали в 5 раз больше, чем Кирилл? Если бы Миша делал бы домашнюю работу по математике в 5 раз дольше, то он бы делал её на 3 часа дольше, чем если бы он её делал в 2 раза быстрее. Сколько времени потратил Миша на домашнюю работу по математике? Помогите!!!!!!!!!!!!

Answer 1

Кир+3,5 = Кол

Тан = 2 Кол

Кир + Кол + Тан = 5 Кир

Это система уравнений. Замени буквами х,у,z и реши. Правильный ответ Коля собрал 14 кг

Answer 2

Problem Statement

Three children, Kolya, Kirill, and Tanya, collected scrap metal. Kolya collected 3.5 kg more than Kirill, and Tanya collected twice as much as Kolya. If the three of them collected 5 times more than Kirill, how much scrap metal did Kolya collect?

Additionally, if Misha spent 3 hours longer on his math homework by doing it 5 times slower, compared to doing it 2 times faster, how much time did Misha spend on his math homework?

Solution

Let's solve the two problems step by step.

# Problem 1: Scrap Metal Collection

We are given the following information: - Kolya collected 3.5 kg more than Kirill. - Tanya collected twice as much as Kolya. - The three of them collected 5 times more than Kirill.

Let's assume that Kirill collected x kg of scrap metal.

According to the given information: - Kolya collected x + 3.5 kg. - Tanya collected 2 * (x + 3.5) kg.

The total amount of scrap metal collected by all three of them is 5 times more than what Kirill collected. Therefore, the total amount is 5 * x kg.

To find the amount of scrap metal collected by Kolya, we can set up the following equation:

x + (x + 3.5) + 2 * (x + 3.5) = 5 * x

Simplifying the equation:

4x + 10.5 = 5x

Rearranging the equation:

10.5 = 5x - 4x

10.5 = x

Therefore, Kirill collected 10.5 kg of scrap metal.

To find the amount of scrap metal collected by Kolya, we substitute the value of x into the equation:

Kolya = x + 3.5 = 10.5 + 3.5 = 14 kg

Therefore, Kolya collected 14 kg of scrap metal.

# Problem 2: Misha's Math Homework

We are given the following information: - If Misha did his math homework 5 times slower, he would spend 3 hours longer. - If Misha did his math homework 2 times faster, he would spend less time.

Let's assume that the original time Misha spent on his math homework is t hours.

According to the given information: - If Misha did his math homework 5 times slower, he would spend t + 3 hours. - If Misha did his math homework 2 times faster, he would spend less time.

From this, we can set up the following equation:

t + 3 = 5t

Simplifying the equation:

3 = 5t - t

3 = 4t

Rearranging the equation:

t = 3/4

Therefore, Misha spent 3/4 hours on his math homework.

Note: The given information does not provide a specific unit of time, so we assume it is in hours.

Answer

Based on the given information: - Kolya collected 14 kg of scrap metal. - Misha spent 3/4 hours on his math homework.