Question

Преобразуйте в могочлен выражения (x-2)во 2 степени -( x-1)(x+2)

Answer 1

(x-2)² - ( x-1)(x+2)Вообще, это уже многочлен. Если вас просили упростить,то: (x² - 2*x*2 + 2²) - (x-1)(x+2)

(x² - 4x + 4) - (x² + 2x - x - 2) 

(x² - 4x + 4) - (x² - x - 2) 

x² - 4x + 4 - x² + x + 2

 Приведем подобные
х² сокращается, тк -х² + х² = 0

(-4х + х) + (4 + 2) 
-3х + 6
Можно взять в скобки:
3(-х + 2) 

Answer 2

Polynomial Expression Transformation

To transform the expression *(x-2)^2 - (x-1)(x+2)*, we can expand and simplify it step by step.

First, let's expand *(x-2)^2*: *(x-2)^2 = x^2 - 4x + 4*.

Now, let's expand *(x-1)(x+2)*: *(x-1)(x+2) = x^2 + 2x - x - 2 = x^2 + x - 2*.

So, the original expression becomes: *(x-2)^2 - (x-1)(x+2) = (x^2 - 4x + 4) - (x^2 + x - 2)*.

Simplifying further: *(x^2 - 4x + 4) - (x^2 + x - 2) = x^2 - 4x + 4 - x^2 - x + 2*.

Finally, combining like terms: *x^2 - 4x + 4 - x^2 - x + 2 = -5x + 6*.

So, the transformed expression is -5x + 6.

This transformation is based on the expansion and simplification of the given polynomial expression.