Question

Помогите!срочно! 4×(a+8)-7(a-1)<12

Answer 1

4а+32-7а+7<12;
4а-7а<-32+12-7;
-3а<-27;
а>9(знак поменялся так как делили отрицательные числа).

Answer 2

I can help you with your math problem. Here is how you can solve it:

First, you need to simplify the left side of the inequality by using the distributive property. You get:

$$4a + 32 - 7a + 7 < 12$$

Then, you need to combine the like terms on the left side by adding or subtracting them. You get:

$$-3a + 39 < 12$$

Next, you need to isolate the variable $a$ by subtracting $39$ from both sides of the inequality. You get:

$$-3a < -27$$

Finally, you need to divide both sides by $-3$ to get the value of $a$. Remember that when you divide by a negative number, you need to flip the inequality sign. You get:

$$a > 9$$

This is the answer. It means that any value of $a$ that is greater than $9$ will make the inequality true. For example, if $a = 10$, then you get:

$$4 \times (10 + 8) - 7(10 - 1) < 12$$

$$4 \times 18 - 7 \times 9 < 12$$

$$72 - 63 < 12$$

$$9 < 12$$

This is a true statement, so $a = 10$ is a valid solution. You can check other values of $a$ that are greater than $9$ and see that they also work.Ответь+подробно.+Помогите!срочно!+4×(a+8)-7(a-1)<12