Вопрос задан 28.04.2019 в 01:14. Предмет Математика. Спрашивает Бисерова Аня.

А)За первые 14 рабочих дней квартала завод изготовил 560 одинаковых стиральных машин,а затем стал

изготовлять в день на 5 таких машин больше.Сколько машин выпустил завод в первые 20 дней квартала? б)Туристу надо было пройти 27 км.Ранним утром он шёл со скоростью 5 км/ч,затем следующие 2 ч со скоростью 4 км/ч,а остальной путь он прошёл за 3 ч.Чему была равна его скорость на последнем участке пути,если скорость на этом участке пути не менялась?
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Отвечает Вековищева Лилия.
1)560÷14=40(машин)— за один день.
2)40+5=45(машин) — изготовляли потом.
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Отвечает нейросеть ChatGpt. Будьте внимательны, ответы нейросети могут содержать ошибочные или выдуманные данные.

Calculating the Number of Washing Machines Produced

To calculate the total number of washing machines produced in the first 20 days of the quarter, we can use the information provided.

The factory initially produced 560 identical washing machines in the first 14 working days and then increased its production by 5 machines per day.

Step 1: Calculate the total number of machines produced in the first 14 days. - Number of machines produced in the first 14 days = 560

Step 2: Calculate the additional machines produced after the 14th day. - Additional machines produced per day = 5 - Number of additional days after the 14th day = 20 - 14 = 6 - Total additional machines produced = 5 * 6

Step 3: Calculate the total number of machines produced in the first 20 days. - Total machines produced in the first 20 days = (Number of machines produced in the first 14 days) + (Total additional machines produced)

Let's calculate the total number of machines produced in the first 20 days.

Solution:

- Number of machines produced in the first 14 days = 560 - Additional machines produced per day = 5 - Number of additional days after the 14th day = 20 - 14 = 6 - Total additional machines produced = 5 * 6 - Total machines produced in the first 20 days = 560 + (5 * 6)

Now, let's calculate the total number of machines produced in the first 20 days.

Calculation:

- Total machines produced in the first 20 days = 560 + (5 * 6) = 560 + 30 = 590

Answer: The factory produced 590 washing machines in the first 20 days of the quarter.

Calculating the Tourist's Speed on the Last Leg of the Journey

To calculate the tourist's speed on the last leg of the journey, we can use the information provided about the distances traveled and the time taken at different speeds.

The tourist walked 27 km, initially at a speed of 5 km/h, then for the next 2 hours at a speed of 4 km/h, and finally covered the remaining distance in 3 hours.

Step 1: Calculate the distance covered at the initial speed of 5 km/h. - Distance covered at 5 km/h = 5 km/h * t1 (where t1 is the time taken at 5 km/h)

Step 2: Calculate the distance covered at the speed of 4 km/h for the next 2 hours. - Distance covered at 4 km/h = 4 km/h * 2 hours

Step 3: Calculate the remaining distance and the time taken to cover it. - Remaining distance = Total distance - (Distance covered at 5 km/h + Distance covered at 4 km/h) - Time taken to cover the remaining distance = 3 hours

Step 4: Calculate the speed on the last leg of the journey. - Speed on the last leg = Remaining distance / Time taken to cover the remaining distance

Let's calculate the speed on the last leg of the journey.

Solution:

- Total distance to be covered = 27 km - Speed for the first part of the journey = 5 km/h - Time taken for the first part of the journey = t1 - Speed for the second part of the journey = 4 km/h - Time taken for the second part of the journey = 2 hours - Time taken for the last part of the journey = 3 hours

Now, let's calculate the speed on the last leg of the journey.

Calculation:

- Distance covered at 5 km/h = 5 km/h * t1 - Distance covered at 4 km/h = 4 km/h * 2 hours - Remaining distance = 27 km - (Distance covered at 5 km/h + Distance covered at 4 km/h) - Speed on the last leg = Remaining distance / Time taken for the last part of the journey

Answer: The speed on the last leg of the journey was the remaining distance divided by the time taken to cover it.

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