Question

Найти определенный интеграл

Answer 1

T=1-x²⇒dt=-2xdx
$\int\limits^2_1 {x/ \sqrt[3]{(1-x^2)^2} } \, dx =-1/2 \int\limits { \sqrt[3]{t^2} } \, dt =-3/2* \sqrt[3]{t} =-3/2* \sqrt[3]{1-x^2} |2-$$1=-3/2* \sqrt[3]{-3} +3/2* \sqrt[3]{0} =3 \sqrt[3]{3} /2$

Answer 2

Finding a Specific Integral

To find a specific integral, we need more information about the function and the limits of integration. Could you please provide the function and the interval over which you would like to evaluate the integral? Once we have that information, we can proceed with finding the integral.