Question

В семье четверо детей. Им 5, 8, 13, 15 лет. Детей зовут Аня, Боря, Вера, Галя. Сколько лет каждому ребёнку, если одна девочка ходит в детский ад, Аня старше Бори, и сумма лет Ани и Веры делится на 3.

Answer 1

Гале 15 лет, Ане 13 лет, Боре 8 лет, Вере 5 лет.
Аня старше Бори - 13 больше, чем 8;
Одна девочка ходит в детский сад - Вере 5 лет, она ходит в детский сад;
Сумма лет Ани и Веры делится на 3 - 13 + 5 = 18; 18 : 3 = 6; Сумма их лет делится на 3.

Answer 2

Problem Analysis

We are given a family with four children, and we need to determine the ages of each child based on the following information: - One girl goes to daycare. - Anya is older than Borya. - The sum of Anya's and Vera's ages is divisible by 3.

Let's analyze the given information and solve the problem step by step.

Solution

1. We know that one girl goes to daycare. Since there are four children, this means that there is only one girl. Let's assign the name "Anya" to the girl.

2. Anya is older than Borya. Let's assign the name "Borya" to the boy.

3. The sum of Anya's and Vera's ages is divisible by 3. Let's assign the names "Vera" and "Galya" to the remaining two children.

Now, let's find the ages of each child.

4. We know that the ages of the children are 5, 8, 13, and 15. Let's assign these ages to the children in the order we determined their names.

- Anya: 15 years old - Borya: 13 years old - Vera: 8 years old - Galya: 5 years old

Therefore, the ages of each child are as follows: - Anya: 15 years old - Borya: 13 years old - Vera: 8 years old - Galya: 5 years old

Please let me know if I can help you with anything else.