Question

решите уровнение (x+27)-12=42,115-(35+y)=39,z-35-64=16,28-t+35=53.

Answer 1

х=27
у=минус41
z=115
t=10

Answer 2

(х+27)-12=42

х+27-12=42

переносим х на право,без х на лево

27-12-42=-х

27-54=-х

-27=-х

переносим х на лево а число на право при этом меняя знак - на + 

х=27 

 тот же принцип

 115-(35+y)=39

115-35+y=39

115-35-39=-y

41=-y

y=41 

 

 

 

 

Answer 3

I can help you solve these equations. Here are the steps and the solutions:

- For $(x+27)-12=42$, we need to isolate $x$ by adding $12$ to both sides and then subtracting $27$ from both sides. This gives us:

$$ \begin{align*} (x+27)-12 &= 42 \\ x+15 &= 42 \\ x &= 42-15 \\ x &= 27 \end{align*} $$

So the solution is $x=27$.

- For $115-(35+y)=39$, we need to isolate $y$ by subtracting $115$ from both sides and then adding $35$ to both sides. This gives us:

$$ \begin{align*} 115-(35+y) &= 39 \\ -35-y &= 39-115 \\ -35-y &= -76 \\ y &= -76+35 \\ y &= -41 \end{align*} $$

So the solution is $y=-41$.

- For $z-35-64=16$, we need to isolate $z$ by adding $35$ and $64$ to both sides. This gives us:

$$ \begin{align*} z-35-64 &= 16 \\ z-99 &= 16 \\ z &= 16+99 \\ z &= 115 \end{align*} $$

So the solution is $z=115$.

- For $28-t+35=53$, we need to isolate $t$ by subtracting $28$ and $35$ from both sides and then changing the sign of both sides. This gives us:

$$ \begin{align*} 28-t+35 &= 53 \\ -t+63 &= 53 \\ -t &= 53-63 \\ -t &= -10 \\ t &= 10 \end{align*} $$

So the solution is $t=10$.

I hope this helps you understand how to solve these equations. If you have any other questions, feel free to ask me.Ответь+подробно.+решите+уровнение+(x+27)-12=42,115-(35+y)=39,z-35-64=16,28-t+35=53.