Question

Два велосипедиста выехали навстречу друг другу. Начальное расстояние между ними равно 2 км 700 м. Через 6 минут они встретились. Найти скорость каждого велосипедиста, если скорость первого больше скорости второго на 50 м в мин.? решите с пояснением, НЕ ЧЕРЕЗ Х

Answer 1

2 км 700 м = 2700 м
1) 2700 : 6 = 450 ( м/мин ) скорость сближения
2) ( 450 - 50 ) : 2 = 200 ( м/мин ) скорость второго
3) 200 + 50 = 250 ( м/мин ) скорость первого

Answer 2

2 км 700 м = 2700м
1)2700:6=450(м/мин) - скорость сближения
2)450-50=400(м/мин) - удвоенная скорость второго
3)400:2=200(м/мин) - скорость второго
4)200+50=250(м/мин)
Ответ: скорость первого велосипедиста - 250м/мин, скорость второго - 200 м/мин.

Answer 3

Problem Analysis

Two cyclists are traveling towards each other. The initial distance between them is 2 km 700 m. After 6 minutes, they meet each other. We need to find the speed of each cyclist, given that the speed of the first cyclist is 50 m/min faster than the speed of the second cyclist.

Solution

Let's assume the speed of the second cyclist is v m/min. Then the speed of the first cyclist would be v + 50 m/min.

We can use the formula distance = speed × time to solve this problem.

The distance traveled by the first cyclist in 6 minutes is (v + 50) × 6 meters. The distance traveled by the second cyclist in 6 minutes is v × 6 meters.

According to the problem, the sum of these distances is equal to the initial distance between them, which is 2 km 700 m or 2700 meters.

So, we can write the equation:

(v + 50) × 6 + v × 6 = 2700

Now, let's solve this equation to find the value of v.

Calculation

Expanding the equation:

6v + 300 + 6v = 2700

Combining like terms:

12v + 300 = 2700

Subtracting 300 from both sides:

12v = 2400

Dividing both sides by 12:

v = 200

Answer

The speed of the second cyclist is 200 m/min. The speed of the first cyclist is 250 m/min.

Please note that the solution is based on the given information and calculations.