Question

Сплав состоит из 19 частей алюминия и 2 частей магния (по массе). Какова масса сплава, если в нем магния на 34 кг меньше, чем алюминия?Решить равнением

Answer 1

1)19х-2х=34
17х=34
Х=34:17
Х=2 кг в одной части
2)19+2=21 частей
3)21*2=42 кг масса сплава

Answer 2

Problem Analysis

We are given that an alloy consists of 19 parts of aluminum and 2 parts of magnesium by mass. We need to find the mass of the alloy if there is 34 kg less magnesium than aluminum.

Solution

Let's assume the mass of aluminum in the alloy is x kg. Since there are 19 parts of aluminum, the mass of magnesium in the alloy would be (x - 34) kg.

According to the given information, the mass of aluminum in the alloy is 19x kg, and the mass of magnesium is (x - 34) kg.

To find the total mass of the alloy, we can add the masses of aluminum and magnesium:

Total mass of the alloy = mass of aluminum + mass of magnesium

Total mass of the alloy = 19x + (x - 34)

Simplifying the equation:

Total mass of the alloy = 20x - 34

Now, we can solve this equation to find the mass of the alloy.

Calculation

To solve the equation, we need to equate the total mass of the alloy to a specific value. However, we don't have enough information to determine the exact value of x or the total mass of the alloy. The given equation is incomplete, and we need additional information to solve it.

Please provide the missing information, such as the total mass of the alloy or the value of x, so that we can calculate the mass of the alloy accurately.

If you have any further questions, feel free to ask!