Question

Из двух городов навстречу друг другу одновременно отправились 2 поезда. средняя скорость одного поезда на 10 км/ч больше скорости другого. через 18 ч они встретяться . определить скорость каждого поезда если расстояние между городами 1620 км. 1) 10км/ч *18ч = 180км- значение разности расстояний пройденное первым и вторым поездами как дальше?

Answer 1

Пусть скорость первого "х",тогда у второго "х+10"
скорость сближения равна сумме скоростей "2х+10"
2х+10=1620/18
2х+10=90
2х=80
х=40км/ч скорость первого ,тогда у второго 40+10=50км/ч
проверим 40×18+50×18=1620

Answer 2

Problem Analysis

We are given that two trains start simultaneously from two cities and meet each other after 18 hours. The average speed of one train is 10 km/h greater than the speed of the other train. The distance between the cities is 1620 km. We need to determine the speed of each train.

Solution

Let's assume the speed of the slower train is x km/h. Then the speed of the faster train will be x + 10 km/h.

We can use the formula distance = speed × time to calculate the distance covered by each train.

The distance covered by the slower train in 18 hours is x × 18 km.

The distance covered by the faster train in 18 hours is (x + 10) × 18 km.

According to the problem, the sum of these distances is equal to the total distance between the cities, which is 1620 km.

So we have the equation: x × 18 + (x + 10) × 18 = 1620.

Simplifying the equation, we get: 36x + 180 = 1620.

Solving for x, we find: 36x = 1440.

Dividing both sides by 36, we get: x = 40.

Therefore, the speed of the slower train is 40 km/h and the speed of the faster train is 50 km/h.

Answer

The speed of the slower train is 40 km/h and the speed of the faster train is 50 km/h.