Question

Из пунктов, расстояние между которыми 210 км, вышли одновременно навстречу друг другу два электропоезда. Скорость одного из них на 5 км/ч больше скорости другого. Найдите скорость каждого электропоезда, если они встретились через 2 ч после своего выхода

Answer 1

((x+5)+x)*2=210
(2x+5)*2=210
4x+10=210
4x=210-10
4x=200
x=200:4
x=50
Если x=50, то х+5=50+5=55км/ч
Ответ:50 км\ч и 55км\ч

Answer 2

Problem Analysis

We are given two trains that start simultaneously from two points that are 210 km apart and are moving towards each other. The speed of one train is 5 km/h faster than the speed of the other train. We need to find the speed of each train if they meet after 2 hours.

Solution

Let's assume the speed of the slower train is x km/h. Therefore, the speed of the faster train will be x + 5 km/h.

We know that the distance traveled by each train is equal to the product of its speed and time. Since the trains are moving towards each other, the sum of the distances traveled by both trains will be equal to the total distance between them.

The distance traveled by the slower train in 2 hours is 2x km, and the distance traveled by the faster train in 2 hours is 2(x + 5) km.

According to the problem, the sum of these distances is equal to 210 km:

2x + 2(x + 5) = 210

Simplifying the equation:

2x + 2x + 10 = 210

4x + 10 = 210

4x = 200

x = 50

Therefore, the speed of the slower train is 50 km/h and the speed of the faster train is 55 km/h.

Answer

The speed of the slower train is 50 km/h and the speed of the faster train is 55 km/h.