Question

ПОМОГИТЕ!Из двух посёлков,расстояние между которых 100км,вышли одновременно и пошли в одном направлении две машины:грузавая и легковая.Скорость грузовой машины - 70км\ч.С какой скоростью двигался легковая машина,если она догнала грузовую через 5 часов?

Answer 1

1) 70•5=350 км- проехала грузовая машина
2) 100+350=450 км -проехала легковая машина до встречи
3) 450:5=90 км/час - скорость легковой машины

Ответ: 90 км/час

 

Answer 2

Problem Analysis

We are given two villages that are 100 km apart. A cargo truck and a passenger car start from these villages at the same time and move in the same direction. The speed of the cargo truck is 70 km/h. We need to find the speed of the passenger car if it catches up to the cargo truck after 5 hours.

Solution

Let's assume the speed of the passenger car is v km/h.

The cargo truck travels for 5 hours at a speed of 70 km/h, so the distance it covers is: Distance covered by cargo truck = Speed of cargo truck × Time = 70 km/h × 5 h = 350 km.

The passenger car catches up to the cargo truck, which means it covers the same distance in 5 hours. Therefore, the distance covered by the passenger car is also 350 km.

We can use the formula Distance = Speed × Time to find the speed of the passenger car: 350 km = v km/h × 5 h.

Simplifying the equation, we have: v km/h = 350 km / 5 h = 70 km/h.

Therefore, the speed of the passenger car is 70 km/h.

Answer

The passenger car was moving at a speed of 70 km/h when it caught up to the cargo truck.