
Галчонок прыгает и шагает по ГалчонокГалчонок прыгает и шагает по Галчонок прыгает и шагает по
лучу.Каждый его шаг равен одному делению луча,а каждыйпрыжок-трём делениям.От точки О галчонок сделал 4 прыжка и 5 шагов.В какой точке оноказался?Потом галчонок сделал ещё 5 прыжков и 2 шага.в какой точке он может находиться теперь.сделай чертеж и реши задачу.

Ответы на вопрос

Нарисовать вправо 17 делений.
5 прыжков по три деления это ещё 15 делений и 2 шага = 17 делений. Всего 34 деления.



Problem Analysis
In this problem, we are given that a bird named Galchonok jumps and walks along a ray. Each step of Galchonok is equal to one division of the ray, and each jump is equal to three divisions. We are given that Galchonok made 4 jumps and 5 steps from point O, and we need to determine the point where Galchonok ended up. After that, Galchonok made 5 more jumps and 2 steps, and we need to find the point where Galchonok could be now.Solution
Let's start by solving the first part of the problem, where Galchonok made 4 jumps and 5 steps from point O.To find the point where Galchonok ended up, we can calculate the total distance covered by Galchonok. Since each step is equal to one division and each jump is equal to three divisions, we can calculate the total distance as follows:
Total distance = (5 * 1) + (4 * 3)
Simplifying the above expression, we get:
Total distance = 5 + 12
Total distance = 17 divisions
Since Galchonok started from point O, we can count 17 divisions from point O to find the point where Galchonok ended up.
Now, let's move on to the second part of the problem, where Galchonok made 5 more jumps and 2 steps.
To find the point where Galchonok could be now, we need to calculate the total distance covered by Galchonok in this part. Using the same logic as before, we can calculate the total distance as follows:
Total distance = (2 * 1) + (5 * 3)
Simplifying the above expression, we get:
Total distance = 2 + 15
Total distance = 17 divisions
Since Galchonok started from the point where it ended up in the first part (17 divisions from point O), we can count 17 divisions from that point to find the point where Galchonok could be now.
Diagram
Here is a diagram to illustrate the problem:``` O-------------------> (Ray) | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | |


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