Question

Двумя автомобилями перевезли 60 тонн картофеля.Первым перевезли 20 тонн, а вторым оставшийся картофель одинакова.Грузоподъёмность автомобилей одинакова.-Общее количество рейсов 12.Сколько рейсов сделал каждый автомобиль

Answer 1

60:12 =5 тонн за один рейс (грузоподъемность автомобиля)

20:5=4 рейса сделал первый автомобиль

(60-20):5= 8 рейсов сделал второй автомобиль

Answer 2

60-20=40 тонн перевез 2 автомобиль

20 - это 1/3 от всего

40 - это 2/3 от всего

12 рейсов

1/3 от 12 равна 4 рейсам

2/3 от 12 равны 8 рейсам

1 автомобиль - 4 рейса

2 автомобиль - 8 рейсов

Answer 3

Problem Analysis

We are given that two cars transported a total of 60 tons of potatoes. The first car transported 20 tons, and the second car transported the remaining potatoes. Both cars have the same carrying capacity, and a total of 12 trips were made. We need to determine how many trips each car made.

Solution

Let's assume that the first car made x trips and the second car made y trips.

From the given information, we can form the following equations:

1. The total weight of potatoes transported by the first car: 20x 2. The total weight of potatoes transported by the second car: (60 - 20)x (since the second car transported the remaining potatoes) 3. The total number of trips: x + y = 12

We can solve this system of equations to find the values of x and y.

Solving the Equations

Substituting the values from equations 1 and 2 into equation 3, we get:

20x + (60 - 20)x = 12

Simplifying the equation:

20x + 40x = 12

60x = 12

x = 12/60

x = 1/5

So, the first car made 1/5 of the total trips, which is equivalent to 12/5 trips.

Substituting the value of x back into equation 3, we can find the value of y:

1/5 + y = 12

y = 12 - 1/5

y = 59/5

So, the second car made 59/5 trips.

Answer

Therefore, the first car made 12/5 trips, and the second car made 59/5 trips.