Question

Для отопления домов привезли уголь. В первый день привезли 4 целых 18/25 т угля во второй на 1 целую 13/75 т больше . Сколько всего тонн угля привезли ? ПОЖАЛУЙСТА ОТВЕТЬТЕ БЫСТРО НАДО

Answer 1

4 18/25+1 13/75 = 4 54/75+1 13/75 = 5 67/75 т - во второй день.
5 67/75+4 54/75 = 9 121/75 = 10 46/75 т - за два дня.

Answer 2

To solve this problem, we need to add the amount of coal delivered on the first day to the amount delivered on the second day.

On the first day, 4 whole tons and 18/25 tons of coal were delivered. On the second day, 1 whole ton and 13/75 tons more coal were delivered than on the first day.

To add these amounts, we need to find a common denominator for the fractions. The least common multiple (LCM) of 25 and 75 is 75.

Converting the fractions to have a denominator of 75: - 18/25 = 54/75 - 13/75 = 13/75

Now we can add the amounts of coal delivered on both days:

4 tons + 54/75 tons + 1 ton + 13/75 tons

To add the whole numbers and fractions separately, we can rewrite the expression as:

(4 + 1) tons + (54/75 + 13/75) tons

Simplifying the expression:

5 tons + 67/75 tons

To add the fractions, we need to find a common denominator, which is already 75.

Adding the fractions:

67/75 + 54/75 = 121/75

Now we can rewrite the expression:

5 tons + 121/75 tons

To simplify the expression, we can convert the mixed number to an improper fraction:

5 tons = 375/75 tons

Adding the fractions:

375/75 + 121/75 = 496/75

Therefore, the total amount of coal delivered is 496/75 tons.

Please note that this answer is based on the information provided and the calculations made.