Question

Помогите пожалуйста! 1) -(х+2у)-(2у+х+1)= 2) -7х+2у-(4х+5)= 3) -(2х+2у-5)-(4+2у-7у)= 4) -2(2х+2у-1)+3(3х-4у-1)= 5) -3(7-2х-у)-5(5-4х+2у)= Надо на завтра срочно помогите!

Answer 1

1) -2х-4у-1                                                                                                        2)-11х+2у-5                                                                                                       3)-2х-7у+1                                                                                                        4)5х-16у-1                                                                                                        5)-46+26х-7у

Answer 2

Task:

The user is asking for help with a set of equations. They have provided five equations, and they need assistance in solving them. The user is requesting urgent help.

Solution:

To solve the set of equations, we will use the given equations and solve for the variables. Let's solve each equation step by step:

1) -(х + 2у) - (2у + х + 1) = 0 2) -7х + 2у - (4х + 5) = 0 3) -(2х + 2у - 5) - (4 + 2у - 7у) = 0 4) -2(2х + 2у - 1) + 3(3х - 4у - 1) = 0 5) -3(7 - 2х - у) - 5(5 - 4х + 2у) = 0

Let's solve each equation one by one:

1) -(х + 2у) - (2у + х + 1) = 0 Simplifying the equation, we get: -х - 2у - 2у - х - 1 = 0 -2х - 4у - 1 = 0 -2х - 4у = 1

2) -7х + 2у - (4х + 5) = 0 Simplifying the equation, we get: -7х + 2у - 4х - 5 = 0 -11х + 2у - 5 = 0 -11х + 2у = 5

3) -(2х + 2у - 5) - (4 + 2у - 7у) = 0 Simplifying the equation, we get: -2х - 2у + 5 - 4 - 2у + 7у = 0 -2х + 5у + 1 = 0 -2х + 5у = -1

4) -2(2х + 2у - 1) + 3(3х - 4у - 1) = 0 Simplifying the equation, we get: -4х - 4у + 2 + 9х - 12у - 3 = 0 5х - 16у - 1 = 0 5х - 16у = 1

5) -3(7 - 2х - у) - 5(5 - 4х + 2у) = 0 Simplifying the equation, we get: -21 + 6х + 3у - 25 + 20х - 10у = 0 26х - 7у - 46 = 0 26х - 7у = 46

Now, we have the following system of equations: -2х - 4у = 1 (Equation 1) -11х + 2у = 5 (Equation 2) -2х + 5у = -1 (Equation 3) 5х - 16у = 1 (Equation 4) 26х - 7у = 46 (Equation 5)

To solve this system of equations, we can use various methods such as substitution, elimination, or matrix methods. Let's solve it using the elimination method:

Adding Equation 1 and Equation 3, we get: (-2х - 4у) + (-2х + 5у) = 1 + (-1) -4х + у = 0 (Equation 6)

Multiplying Equation 2 by 2 and adding it to Equation 6, we get: (-22х + 4у) + (-4х + у) = 10 + 0 -26х + 5у = 10 (Equation 7)

Multiplying Equation 4 by 2 and adding it to Equation 7, we get: (10х - 32у) + (-26х + 5у) = 2 + 10 -16х - 27у = 12 (Equation 8)

Multiplying Equation 8 by 26 and adding it to Equation 5, we get: (-416х - 702у) + (26х - 7у) = -312 + 46 -390х - 709у = -266 (Equation 9)

Now, we have the following system of equations: -16х - 27у = 12 (Equation 8) -390х - 709у = -266 (Equation 9)

To solve this system of equations, we can use the elimination method again:

Multiplying Equation 8 by 390 and adding it to Equation 9, we get: (-6240х - 10530у) + (-390х - 709у) = 4680 + (-266) -6630у = 4414 у = -4414/6630 у ≈ -0.6667

Substituting the value of у into Equation 8, we get: -16х - 27(-0.6667) = 12 -16х + 18 ≈ 12 -16х ≈ -6 х ≈ 0.375

Therefore, the approximate solution to the given system of equations is: х ≈ 0.375 у ≈ -0.6667

Please note that these are approximate solutions, and the actual solutions may vary depending on the accuracy required.

I hope this helps! Let me know if you have any further questions.