Question

Решите задачи, делая приближенные вычисления а)Прокладывая маршрут по карте, путешественники определили, что от Кейптауна до Дурбана 1295 км, а от Дурбана до мыса Вухимена 1418км.Самолет может пролететь без дозаправки 30 сотен километров.Сколько приблизительно сотен километров от Кейптауна до мыса Вухимена?Можно ли по этому маршруту совершить беспосадочный перелет на самолете? б)Самолет может взять на борт не более 3т груза.Для отправки приготовили 5035 кг груза, но затем по требованию пилота убрали 1027 кг.Можно ли загружать оставшийся груз в самолет?А если бы убрали 2027кг?ПОМГИТЕ ПОБЫСТРЕЙ

Answer 1

1295+1418=2713(км) это примерно 27 сотен км расстояние от Кейптауна до Вухимена Ответ:самолет может совершить беспосадочны перелет. 5035-1027+4008(кг)-возьмет на борт не больше 3-х тонн.Ответ:Груз загружать нельзя.

Answer 2

Problem Analysis

To solve this problem, we need to determine the approximate distance in hundreds of kilometers from Cape Town to Cape Vuhimena and whether it is possible to make a non-stop flight on a plane. We also need to determine if it is possible to load the remaining cargo onto the plane, given its weight restrictions.

Solution

a) To find the approximate distance in hundreds of kilometers from Cape Town to Cape Vuhimena, we can add the distances from Cape Town to Durban and from Durban to Cape Vuhimena. The given distances are 1295 km from Cape Town to Durban and 1418 km from Durban to Cape Vuhimena.

The total distance is 1295 km + 1418 km = 2713 km.

Since the plane can fly without refueling for 300 km, we can divide the total distance by 300 to find the number of hundreds of kilometers the plane can fly without refueling.

2713 km ÷ 300 km = 9.0433

Therefore, the approximate distance in hundreds of kilometers from Cape Town to Cape Vuhimena is approximately 9 hundred kilometers.

b) The plane can carry a maximum of 3 tons of cargo, which is equivalent to 3000 kg. Initially, 5035 kg of cargo was prepared, but 1027 kg was removed upon the pilot's request.

If 1027 kg of cargo is removed, the remaining weight is 5035 kg - 1027 kg = 4008 kg.

Since the plane can carry a maximum of 3000 kg, it is not possible to load the remaining cargo onto the plane.

If 2027 kg of cargo is removed, the remaining weight is 5035 kg - 2027 kg = 3008 kg.

Since the plane can carry a maximum of 3000 kg, it is possible to load the remaining cargo onto the plane.

Therefore, if 2027 kg of cargo is removed, it is possible to load the remaining cargo onto the plane.

I hope this helps! Let me know if you have any further questions.