Question

Один вертолет пролетел 3600км а другой 2400км.Первый вертолет был в полете на 3 ч дольше второго.Сколько часов летел каждый вертолет если они двигались с одинаковой скоростью????

Answer 1

1)3600-2400=1200 (км) разница между расстоянием которое преодолели оба вертолёта.

Нам известно, что первый вертолет был в полете на 3 часа больше второго, значит он за эти три часа и пролетел эти 1200 км. Нам известно теперь расстояние и время, значит можно найти скорость вертолетов(она у них одинаковая)

2)1200:3=400(км/ч) это скорость вертолёта

Теперь у нас есть скорость и расстояние, а нужно найти время.

3)3600:400=9 (ч) в полете был первый вертолет

Время полета второго вертолета можно найти 2 способами, выбирай любой.

Либо так же, как и первого - расстояние разделить на скорость

4)2400:400=6 (ч)

Либо зная, что первый летал 9 часов(это в третьем действии мы нашли), а его полет длился на 3 часа больше второго (это в условии задачи сказано), то так:

4)9-3=6(ч)

Answer 2

3 600-2 400=1 200 - разница во времени полета
1 200:3=400 км/час скорость
3 600:400=9 часов - 1 вертолет
2 400:400=6 часов -2 вертолет

Answer 3

Problem Analysis

We are given two helicopters that traveled different distances. The first helicopter flew 3600 km, while the second helicopter flew 2400 km. The first helicopter was in the air for 3 hours longer than the second helicopter. We need to determine how long each helicopter was in the air if they were traveling at the same speed.

Solution

Let's assume that both helicopters were traveling at a constant speed of x km/h. Since speed is equal to distance divided by time, we can set up the following equations:

For the first helicopter: 3600 km = x km/h * t1

For the second helicopter: 2400 km = x km/h * t2

We also know that the first helicopter was in the air for 3 hours longer than the second helicopter: t1 = t2 + 3

To solve this system of equations, we can substitute the value of t1 from the third equation into the first equation:

3600 km = x km/h * (t2 + 3)

Now we can solve for t2:

3600 km = x km/h * t2 + 3x km/h

3600 km - 3x km/h = x km/h * t2

t2 = (3600 km - 3x km/h) / x km/h

Similarly, we can solve for t1 using the value of t2:

t1 = t2 + 3

t1 = [(3600 km - 3x km/h) / x km/h] + 3

Now we have expressions for t1 and t2 in terms of x. To find the values of t1 and t2, we need to find the value of x that satisfies both equations.

Let's solve for x using the given information.

Calculation

To find the value of x, we need to solve the equation:

2400 km = x km/h * t2

Substituting the expression for t2, we get:

2400 km = x km/h * [(3600 km - 3x km/h) / x km/h]

Simplifying the equation:

2400 km = (3600 km - 3x km/h)

3x km/h = 3600 km - 2400 km

3x km/h = 1200 km

x km/h = 1200 km / 3

x km/h = 400 km/h

Now that we have the value of x, we can substitute it back into the expressions for t1 and t2 to find the values of t1 and t2.

t1 = [(3600 km - 3(400 km/h)) / (400 km/h)] + 3

t1 = (3600 km - 1200 km) / 400 km/h + 3

t1 = 2400 km / 400 km/h + 3

t1 = 6 hours + 3 hours

t1 = 9 hours

t2 = (3600 km - 3(400 km/h)) / (400 km/h)

t2 = (3600 km - 1200 km) / 400 km/h

t2 = 2400 km / 400 km/h

t2 = 6 hours

Therefore, the first helicopter flew for 9 hours, while the second helicopter flew for 6 hours, assuming they were traveling at the same speed.

Answer

The first helicopter flew for 9 hours, while the second helicopter flew for 6 hours if they were traveling at the same speed.

Please let me know if I can help you with anything else.