Question

В первом баке в 4 раза больше жидкости чем во втором. Когда из первого бака перелили 10 л жидкости во второй оказалось что во втором баке стало в 1,5 раза больше жидкости чем осталось в первом баке сколько жидкости было в каждом баке

Answer 1

X -во втором баке
4x -в первом баке
4x-10  -осталось в первом баке
x+10  -стало во втором баке
1,5*(4x-10)=x+10
6x-15=x+10
6x-x=10+15
5x=25
x=25:5
x=5 литров было во втором баке
5*4=20 литров было в первом баке

Answer 2

Пусть в первом баке изначально было x литров, а во втором баке - y литров. Тогда по условию
x = 4y,
1,5*(x-10) = y+10,
Решаем эту систему уравнений,
1,5*(4y - 10) = y+10,
6y - 15 = y+10,
5y = 25,
y= 25/5 = 5 литров,
x = 4*5 = 20 литров.

Answer 3

Problem Statement

We are given the following information: - In the first tank there is 4 times as much liquid as in the second tank - 10L of liquid was poured from the first tank into the second tank - After the pouring, there was 1.5 times as much liquid in the second tank as what remained in the first tank

We need to find: - How much liquid was originally in each tank

Solving the Problem

Let's call the amount of liquid originally in the second tank x liters Then the amount originally in the first tank is 4x liters (since it's 4 times the second tank)

After pouring 10L from the first to the second tank: - First tank: 4x - 10 liters - Second tank: x + 10 liters

It's given that after pouring, the second tank had 1.5 times as much liquid as the first tank. So: x + 10 = 1.5 * (4x - 10) x + 10 = 6x - 15 5x = 25 x = 5

Therefore: - Original amount in second tank: 5 liters - Original amount in first tank: 4 * 5 = 20 liters

So the amounts originally in each tank were: - Second tank: 5 liters - First tank: 20 liters