Question

Помогите решить задачу с системой уравненийв двух бидонах 28л жидкости .если из первого бидона перелить 2 л жидкости во второй то обьем жидкости в обоих бидонах будет одинаковым.сколько литров жидкости было в каждом бидонах первоначально?

Answer 1

2-й вариант решения
х - литров в 1-ом бидоне
у - литров во 2-ом бидоне
х + у = 28
х - 2 - литра стало в 1-ом бидоне
у + 2 - стало во 2-ом бидоне
х - 2 = у + 2
Система уравнений:
х + у = 28 => x = 28 - y
х - 2 = у + 2 => x - y = 4 => x = 4 + y
28 - y = 4 + y
2y = 24
y = 12
x = 4 + y = 4 + 12 = 16
Ответ: 12 и 16 литров

Answer 2

Problem Analysis

To solve this problem, we need to find the initial amount of liquid in each container. Let's assume that the initial amount of liquid in the first container is x liters.

According to the problem, if we transfer 2 liters from the first container to the second container, the total volume of liquid in both containers will be the same.

Solution

Let's solve this problem step by step:

1. Initially, the first container has x liters of liquid. 2. After transferring 2 liters from the first container to the second container, the first container will have (x - 2) liters of liquid, and the second container will have 2 liters of liquid. 3. The total volume of liquid in both containers is 28 liters. So, we can write the equation: (x - 2) + 2 = 28. 4. Simplifying the equation, we get: x - 2 + 2 = 28. 5. The -2 and +2 cancel each other out, leaving us with x = 28. 6. Therefore, the initial amount of liquid in each container was 28 liters.

Answer

The initial amount of liquid in each container was 28 liters.

Please let me know if you need any further assistance!