Question

(побудуваты прями) a) 2x+3y=0, b) 5x-2=0, c) 2y+7=0

Answer 1

А ) х=0,у=0, b)x=1,4, c)y=3,5

Answer 2

Solving the System of Equations

To solve the system of equations, let's consider each equation one by one:

a) 2x + 3y = 0 b) 5x - 2 = 0 c) 2y + 7 = 0

Let's start with equation a:

To find the value of x, we can isolate x by subtracting 3y from both sides of the equation:

2x + 3y - 3y = 0 - 3y 2x = -3y

Dividing both sides of the equation by 2, we get:

x = -3y/2

Now, let's move on to equation b:

To find the value of x, we can isolate x by adding 2 to both sides of the equation:

5x - 2 + 2 = 0 + 2 5x = 2

Dividing both sides of the equation by 5, we get:

x = 2/5

Finally, let's consider equation c:

To find the value of y, we can isolate y by subtracting 7 from both sides of the equation:

2y + 7 - 7 = 0 - 7 2y = -7

Dividing both sides of the equation by 2, we get:

y = -7/2

Solution:

Therefore, the solution to the system of equations is: - x = 2/5 - y = -7/2

Please let me know if there's anything else I can help you with!