Question

Мастер и ученик могут выполнить работу за 17ч,За какое время ученик один сможет выполнить всю работу, Если ему потребуется на это 20ч больше,чем мастеру?

Answer 1

Х - работа мастера
(х + 20) - работа ученика
Получаем уравнение:
х+х+20=17
2х=20+17
2х=37
х=18,5 (это работа мастера)
18,5+20=38,5 (ч) - работа одного ученика

Answer 2

Calculation of Time for the Master and Apprentice to Complete the Work

To determine the time it would take for the apprentice to complete the entire work on their own, given that it would take them 20 hours longer than the master, we can set up the following equation:

Time taken by the master + 20 hours = Time taken by the apprentice

Let's denote the time taken by the master as M and the time taken by the apprentice as A.

According to the given information, the master and apprentice can complete the work together in 17 hours. Therefore, we have:

M + A = 17 We also know that the apprentice would take 20 hours longer than the master to complete the work:

A = M + 20

Now we can substitute the value of A from the second equation into the first equation:

M + (M + 20) = 17

Simplifying the equation:

2M + 20 = 17

2M = 17 - 20

2M = -3

M = -3/2

Since time cannot be negative, this result is not valid. It seems there might be an error in the given information or calculation. Could you please double-check the values provided?