Question

решите плиз. 7*(1,2х +0,3у)+(9,3х +0,6у)*2 при х= 0,1 ,у=1 завтра зачет а я не готова

Answer 1

7*(1,2х +0,3у)+(9,3х +0,6у)*2=8,4х+2,1у+18,6х+1,2у=27х+3,3у=27*0,1+3,3*1=  2,7+3,3=6

 

Answer 2

Calculating the Expression

To solve the given expression 7*(1.2x + 0.3y) + (9.3x + 0.6y)*2 when x = 0.1 and y = 1, we can substitute the given values of x and y into the expression and then perform the calculations.

Substituting x = 0.1 and y = 1 into the expression: 7*(1.2*0.1 + 0.3*1) + (9.3*0.1 + 0.6*1)*2

Simplifying the expression: 7*(0.12 + 0.3) + (0.93 + 0.6)*2 7*(0.42) + (1.53)*2 2.94 + 3.06 The value of the expression when x = 0.1 and y = 1 is 6.