Question

В сосуд,имеющий форму правильной треугольной призмы налили воду.Уровень воды достигает 10 см.На какой высоте будет находиться уровень воды,если ее перелить в другой такой же сосуд,у которого сторона основания в 5раз больше,чем у первого?

Answer 1

10:5=2
На высоте в 2 см

Answer 2

Calculation of the Water Level in the Second Vessel

To calculate the height at which the water level will be in the second vessel, we need to consider the ratio of the base areas of the two vessels.

Given that the base of the second vessel is 5 times larger than the base of the first vessel, we can calculate the ratio of the base areas as follows:

Base area of the second vessel / Base area of the first vessel = 5^2 = 25.

Since the water level in the first vessel is at a height of 10 cm, we can calculate the height at which the water level will be in the second vessel using the following formula:

Height in the second vessel = (Height in the first vessel) * (Base area of the second vessel / Base area of the first vessel).

Substituting the values, we get:

Height in the second vessel = 10 cm * 25 = 250 cm.

Therefore, the water level in the second vessel will be at a height of 250 cm.

Please note that the calculations assume that the volume of water remains constant when transferred from one vessel to another.