Question

В 1 сосуд налили m жидкости,во 2 налили на 7 л меньше чем в первый,а в третий сосуд налили на 10 л больше,чем во второй,известно что в 3 сосуде оказалось столько жидкости,сколько и в 1 и 2 сосуде

Answer 1

M+10=m+m-7
m-m-m=-7-10
-m=-17
m=17
17-10=7л
ответ:7 л 

Answer 2

Problem Analysis

We have three vessels: vessel 1, vessel 2, and vessel 3. The amount of liquid in vessel 2 is 7 liters less than the amount in vessel 1, and the amount in vessel 3 is 10 liters more than the amount in vessel 2. We need to find the amount of liquid in vessel 3, which is equal to the combined amount in vessels 1 and 2.

Solution

Let's assume the amount of liquid in vessel 1 is m liters.

According to the given information, the amount of liquid in vessel 2 is 7 liters less than the amount in vessel 1. Therefore, the amount in vessel 2 is m - 7 liters.

Similarly, the amount of liquid in vessel 3 is 10 liters more than the amount in vessel 2. Therefore, the amount in vessel 3 is (m - 7) + 10 liters.

To find the amount of liquid in vessel 3, we need to add the amounts in vessels 1 and 2. Therefore, the amount in vessel 3 is m + (m - 7) + 10 liters.

Calculation

Let's calculate the amount of liquid in vessel 3 using the given information.

The amount in vessel 3 is m + (m - 7) + 10 liters.

Simplifying the expression, we get 2m + 3 liters.

Therefore, the amount of liquid in vessel 3 is 2m + 3 liters.

Answer

The amount of liquid in vessel 3 is 2m + 3 liters.

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