Question

Первый токарь выточил у деталей.другой на 7 деталей больше.чем первый.а третий на 8 деталей меньше чем второй.вместе они сделали 81 деталь

Answer 1

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Answer 2

Первый у деталей, второй у+7, а третий (у+7)-8. Составим уравнение:
у+(у+7)+(у+7)-8= 81
у+у+7+у+7-8=81

Answer 3

Solution:

Let's solve this step by step.

1. Let's assume the number of parts the first turner made is x. 2. The second turner made 7 more parts than the first turner, so the number of parts the second turner made is x + 7. 3. The third turner made 8 fewer parts than the second turner, so the number of parts the third turner made is (x + 7) - 8.

We know that together they made 81 parts, so we can write the equation:

x + (x + 7) + (x + 7 - 8) = 81

Solving this equation will give us the value of x, which is the number of parts the first turner made.

Let's solve for x:

3x - 1 = 81

3x = 82

x = 27

So, the first turner made 27 parts, the second turner made 27 + 7 = 34 parts, and the third turner made 34 - 8 = 26 parts.

Therefore, the first turner made 27 parts, the second turner made 34 parts, and the third turner made 26 parts.

Answer:

The first turner made 27 parts, the second turner made 34 parts, and the third turner made 26 parts.