Question

Из аэропорта на юг вылетел транспортный самолет, который летел со скоростью 680км/ч. Одновременно с ним на север вылетел пассажирский самолет, который летел со скоростью 780км/ч. на каком расстоянии друг от друга самолеты окажутся через 4 часа ?

Answer 1

1) 680•4=2720(км)
2)780•4=3120(км)
3)2720+3120=5840(км)

Answer 2

Problem Analysis

We are given that a transport plane flew south from an airport at a speed of 680 km/h, while simultaneously a passenger plane flew north from the same airport at a speed of 780 km/h. We need to determine the distance between the two planes after 4 hours.

Solution

To find the distance between the two planes after 4 hours, we need to calculate the distance each plane traveled in that time.

The transport plane flew south at a speed of 680 km/h for 4 hours, so the distance it traveled can be calculated as:

Distance traveled by transport plane = Speed × Time = 680 km/h × 4 hours

Similarly, the passenger plane flew north at a speed of 780 km/h for 4 hours, so the distance it traveled can be calculated as:

Distance traveled by passenger plane = Speed × Time = 780 km/h × 4 hours

To find the distance between the two planes, we need to subtract the distance traveled by the passenger plane from the distance traveled by the transport plane:

Distance between the planes = Distance traveled by transport plane - Distance traveled by passenger plane

Let's calculate the distances:

Distance traveled by transport plane = 680 km/h × 4 hours = 2720 km

Distance traveled by passenger plane = 780 km/h × 4 hours = 3120 km

Distance between the planes = 2720 km - 3120 km = -400 km

The negative distance indicates that the planes are in opposite directions. However, the question asks for the distance between the planes, so we take the absolute value of the result:

Distance between the planes = | -400 km | = 400 km

Therefore, the two planes will be 400 kilometers apart after 4 hours.

Answer

The two planes will be 400 kilometers apart after 4 hours.