Question

Из двух посёлков, расстояние между которыми 2 км, выехали одновременно в одном направлении два велосепидиста. Через 30 минут первый велосепедист догнал второго.С какой скоростью мог двигатся один из велосепедистов, если другой двигался со скоростью 12км/ч?

Answer 1

30мин=0,5ч

Івелос.,едущий впереди -12км/ч

ІІ велос. - ?км/ч

 

1) 12 * 0,5=6(км) - проехал І велосипедист

2) 6+2=8(км) - проехал ІІ велосипедист

Время до встречи одинаковое

3) 8:0,5=16(км/ч) - скорость ІІ велосипедиста.

 

ІІ вариант.Поменяем велосипедистов местами.

 

І велос.,едущий впереди - ?км/ч

II велос.-12км/ч

 

1) 12*0,5=6(км) - проехал ІІ велосипедист

2) 6-2=4(км) - проехал І велосипедист

3) 4;0,5=8(км/ч) - скорость І велосипедиста

Answer 2

Problem Analysis

We have two cyclists who start simultaneously from two villages that are 2 km apart. After 30 minutes, one cyclist catches up to the other. We need to determine the speed at which one of the cyclists was traveling, given that the other cyclist was traveling at a speed of 12 km/h.

Solution

Let's assume that the speed of the cyclist we want to find is x km/h. Since the distance between the two villages is 2 km, the cyclist who catches up to the other must have covered this distance in 30 minutes.

To find the speed of the cyclist we want to find, we can use the formula:

Speed = Distance / Time

The distance covered by the cyclist who catches up to the other is 2 km, and the time taken is 30 minutes (or 0.5 hours). Therefore, we can write the equation as:

x = 2 km / 0.5 hours

Simplifying this equation, we find:

x = 4 km/h

Therefore, the speed at which the cyclist we want to find was traveling is 4 km/h.

Answer

The cyclist we want to find was traveling at a speed of 4 km/h.