Question

Запишіть девяти цифрове число, у якому цифри одного класу однакові, а цифри кожного наступного класу вдвічі більші від цифр попереднього. Скільки розвязків має задача?

Answer 1

444222111 и 888444222
Два числа получчилось

Answer 2

Nine-Digit Number with Specific Properties

To find a nine-digit number where the digits in each class are the same and the digits in each subsequent class are twice as large as the digits in the previous class, we can use the following approach:

Let's denote the digits in the number as follows: - Class 1: a - Class 2: 2a - Class 3: 4a

The number can then be represented as: abc, 2abc, 4abc

Where a, b, and c are the digits in each class.

Number of Solutions

To determine the number of solutions for this problem, we can consider the possible values for a, b, and c. Since a, b, and c are digits, they can take values from 1 to 9.

Let's consider the possible values for a, b, and c: - a can take 1 to 9 (9 possibilities) - b can take 0 to 9 (10 possibilities) - c can take 0 to 9 (10 possibilities)

Therefore, the total number of solutions can be calculated by multiplying the number of possibilities for each digit: Total number of solutions = 9 (possibilities for a) * 10 (possibilities for b) * 10 (possibilities for c) = 900

So, the number of solutions for this problem is 900.