Question

Квартира состоит из трёх комнат. Первая комната на 5кв.м меньше второй, а вторая на 8кв.м меньше третьей. Найдите общую площадь трёх комнат , если площадь самой маленькой из них равна 10кв.м!

Answer 1

Судя по условию задачи,можем сказать ,что самая маленькая комната(с наименьшей площадью)-это первая комната.Так как она меньше второй(на 5м²) и соответственно меньше третьей.

Решаем:

1)10+5=15(м²)-площадь второй комнаты.

2)15+8=23(м²)-площадь третьей.

3)10+15+23=48(м²)-общая площадь трёх комнат.

Answer 2

меньшая комната-первая,тогда

10+5=15 кв м - площадь второй комнаты,

15+8=23 кв м площадь третьей комнаты,

10+15+23=48 кв м площадь всех трех комнат.

Answer 3

Problem Analysis

We are given that an apartment consists of three rooms. The first room is 5 square meters smaller than the second room, and the second room is 8 square meters smaller than the third room. We need to find the total area of the three rooms, given that the smallest room has an area of 10 square meters.

Solution

Let's denote the area of the first room as x square meters.

According to the given information, the second room is 5 square meters larger than the first room, so its area is x + 5 square meters.

Similarly, the third room is 8 square meters larger than the second room, so its area is (x + 5) + 8 square meters.

We are also given that the smallest room has an area of 10 square meters, so we can set up the following equation:

x = 10

Substituting this value of x into the expressions for the areas of the second and third rooms, we can find their areas:

Second room area = (10 + 5) = 15 square meters

Third room area = (15 + 8) = 23 square meters

Finally, we can find the total area of the three rooms by adding up their individual areas:

Total area = 10 + 15 + 23 = 48 square meters

Therefore, the total area of the three rooms is 48 square meters.

Answer

The total area of the three rooms is 48 square meters.