Question

В одной коробке носки голубые, а в другой-белые.голубых носков на 20 пар больше, чем белых, а всего в двух коробках 84 пары носков.сколько пар носков каждого цвета. в магазине имеется крупа трёх видов гречка, перловка и рис, всего 580 кг. если бы продали 44 кг гречки, 18 кг перловки и 29 кг риса, то масса крупы всех видов стала бы одинаковой. сколько кг крупы каждого вида имеется.

Answer 1

1) 84-20=64 — белых и голубых в 2-х коробках,в том случае если бы их было равное количество.
2) 64:2=32 — белых носков.
3) 32+20=52 — голубых носков.

Answer 2

Problem 1: Socks in Boxes

Let's solve the problem step by step:

1. We have two boxes of socks: one with blue socks and the other with white socks. 2. The number of blue socks is 20 pairs more than the number of white socks. 3. The total number of socks in both boxes is 84 pairs.

To find the number of pairs of each color, we can set up a system of equations:

Let x be the number of pairs of white socks. Then the number of pairs of blue socks is x + 20.

The total number of pairs of socks is the sum of the pairs of white and blue socks: x + (x + 20) = 84.

Simplifying the equation: 2x + 20 = 84, 2x = 64, x = 32.

So, there are 32 pairs of white socks and 52 pairs of blue socks.

Problem 2: Types of Groats

Let's solve the problem step by step:

1. There are three types of groats: buckwheat, pearl barley, and rice. 2. The total weight of all the groats is 580 kg. 3. If 44 kg of buckwheat, 18 kg of pearl barley, and 29 kg of rice were sold, the total weight of all the groats would be the same.

To find the weight of each type of groats, we can set up a system of equations:

Let x be the weight of buckwheat, y be the weight of pearl barley, and z be the weight of rice.

The total weight of all the groats is the sum of the weights of buckwheat, pearl barley, and rice: x + y + z = 580.

If 44 kg of buckwheat, 18 kg of pearl barley, and 29 kg of rice were sold, the total weight of all the groats would be the same: (x - 44) + (y - 18) + (z - 29) = 580.

Simplifying the equations: x + y + z = 580, x + y + z = 671.

Subtracting the first equation from the second equation: (x - 44) + (y - 18) + (z - 29) - (x + y + z) = 671 - 580, -44 - 18 - 29 = 91, -91 = 91.

This is not a valid equation, which means there is no solution that satisfies the given conditions. Therefore, we cannot determine the weight of each type of groats.

Please let me know if there is anything else I can help you with!